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When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is (Given molar mass in g mol –1 H : 1, C : 12, N : 14, O : 16, S : 32)
- 343
- 33
- 66
- 330
Correct answer: 33
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