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Energy released when two deuterons ( 1 H 2 ) fuse to form a helium nucleus ( 2 He 4 ) is (Given: Binding energy per nucleon of 1 H 2 = 1.1 MeV and binding energy per nucleon of 2 He 4 = 7.0 MeV)
- 23.6 MeV
- 5.9 MeV
- 8.1 MeV
- 26.8 MeV
Correct answer: 23.6 MeV
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