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An optically active alkyl halide C 4 H 9 Br [A] reacts with hot KOH dissolved in ethanol and forms alkene [B] as major product which reacts with bromine to give dibromide [C]. The compound [C] is converted into a gas [D] upon reacting with alcoholic NaNH 2 . During hydration 18 gram of water is added to 1 mole of gas [D] on warming with mercuric sulphate and dilute acid at 333 K to form compound [E]. The IUPAC name of compound [E] is :

1. Butan-1-al
2. But-2-yne
3. Butan-2-one
4. Butan-2-ol

Correct answer: Butan-2-one

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