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If the solution y = y(x) of the differential equation (x 4 + 2x 3 + 3x 2 + 2x + 2) dy – (2x 2 + 2x + 3) dx = 0 satisfies y(–1) = 4 π − , then y(0) is equal to-

1. 12 π −
2. 0
3. 4 π
4. 2 π

Correct answer: 4 π

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