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ExamsJEE MainGeneral

The vertices of a triangle are A(–1, 3), B(–2, 2) and C(3, –1). A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :

  1. x – y – (2 + 2 ) = 0
  2. –x + y – (2 – 2 ) = 0
  3. x + y – ) 2 2 ( − = 0
  4. ) 2 2 ( y x − + + = 0

Correct answer: x + y – ) 2 2 ( − = 0

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