Exams › JEE Main › General
Let α , β , γ , δ ∈ Z and let A ( α , β ), B (1, 0), C ( γ , δ ) and D(1, 2) be the vertices of a parallelogram ABCD. If AB = 10 and the points A and C lie on the line 3y = 2x + 1, then 2( α + β + γ + δ ) is equal to
- 10
- 8
- 12
- 5
Correct answer: 8
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