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When a metal surface is illuminated by light of wavelength λ , the stopping potential is 8V. When the same surface is illuminated by light of wavelength 3 λ , stopping potential is 2V. The threshold wavelength for this surface is:
- 3 λ
- 4.5 λ
- 9 λ
- 5 λ
Correct answer: 9 λ
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