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A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60° by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is [g = 10 m/s 2 ] 60 o 10N M μ s = 0.1

1. 5 J
2. 3 5 J
3. 5 × 10 3 J
4. 10 J

Correct answer: 5 J

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