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If the total energy transferred to a surface in time t is 6.48 × 10 5 J, then the magnitude of the total momentum delivered to this surface for complete absorption will be :
- 2.46 × 10 –3 kg m/s
- 4.32 × 10 –3 kg m/s
- 1.58 × 10 –3 kg m/s
- 2.16 × 10 –3 kg m/s
Correct answer: 2.16 × 10 –3 kg m/s
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