Exams › JEE Main › General
A particle of charge '–q' and mass 'm' moves in a circle of radius 'r' around an infinitely long line charge of linear charge density '+ λ '. Then time period will be given as : (Consider k as Coulomb's constant)
- T = q k 2 m r 2 1 λ π
- T 2 = q k 2 m 4 2 λ π r 3
- T = 2 π r q k 2 m λ
- T = m q k 2 2 1 λ π
Correct answer: T = 2 π r q k 2 m λ
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →