Exams › JEE Main › General
The atomic mass of 6 C 12 is 12.000000 u and that of 6 C 13 is 13.003354 u. The required energy to remove a neutron from 6 C 13 , if mass of neutron is 1.008665 u, will be :
- 49.5 MeV
- 62.5 MeV
- 6.25 MeV
- 4.95 MeV
Correct answer: 4.95 MeV
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →