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If tanA = 2 1 x(x x 1) + + , tanB = 2 x x x 1 + + and tanC = (x –3 + x –2 + x –1 ) 1/2 , 0 < A, B, C < 2 π , then A + B is equal to :
2 π – C
C
2 π – C
π – C
Correct answer:
C
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