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Arrange the bonds in order of increasing ionic character in the molecules. LiF, K 2 O, N 2 , SO 2 and ClF 3 .

1. LiF < K 2 O < ClF 3 < SO 2 < N 2
2. N 2 < SO 2 < ClF 3 < K 2 O < LiF
3. ClF 3 < N 2 < SO 2 < K 2 O < LiF
4. N 2 < ClF 3 < SO 2 < K 2 O < LiF

Correct answer: N 2 < SO 2 < ClF 3 < K 2 O < LiF

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