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A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle θ to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection θ is then given by:

1. 1 2 2 1 2 2gT cos R − ⎡ ⎤ ⎢ ⎥ π ⎢ ⎥ ⎣ ⎦
2. 1 2 2 1 2 2gT sin R − ⎡ ⎤ ⎢ ⎥ π ⎢ ⎥ ⎣ ⎦
3. 1 2 2 1 2 R sin 2gT − ⎡ ⎤ π ⎢ ⎥ ⎢ ⎥ ⎣ ⎦
4. 1 2 1 2 R cos 2gT − ⎡ ⎤ π ⎢ ⎥ ⎢ ⎥ ⎣ ⎦

Correct answer: 1 2 2 1 2 2gT sin R − ⎡ ⎤ ⎢ ⎥ π ⎢ ⎥ ⎣ ⎦

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