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Electric potential at a point 'P' due to a point charge of 5 × 10 –9 C is 50 V. The distance of 'P' from the point charge is : (Assume, 0 4 1 πε = 9 × 10 9 Nm 2 C –2 )

1. 9 cm
2. 3 cm
3. 0.9 cm
4. 90 cm

Correct answer: 90 cm

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