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A hydraulic automobile lift is designed to lift vechicles of mass 5000 kg. The area of cross section of the cylinder carrying to load is 250 cm 2 . The maximum pressure the smaller piston would have to bear is [Assume g = 10m/s 2 ]
- 20 × 10 +6 Pa
- 2 × 10 +5 Pa
- 200 × 10 +6 Pa
- 2 × 10 +6 Pa
Correct answer: 2 × 10 +6 Pa
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