StreakPeaked· Practice

ExamsJEE MainGeneral

At any instant the velocity of a particle of mass 500 g is 1 2 ms ) j ˆ t 3 i ˆ t 2 ( − + . If the force acting on the particle at t = 1s is ) j ˆ x i ˆ ( + N. Then the value of x will be:

  1. 3
  2. 4
  3. 2
  4. 6

Correct answer: 3

Related JEE Main General questions

⚔️ Practice JEE Main General free + battle 1v1 →