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Let a 1 = 1, a 2 , a 3 , a 4 ,…. be consecutive natu ral numbers. Then tan – 1          2 1 a a 1 1 + tan − 1          3 2 a a 1 1 +.....+ tan − 1          2022 2021 a a 1 1 is equal to

1. tan − 1 (2022) – 4 
2. cot – 1 ( 2022 ) – 4 
3. 4  − cot – 1 (2022)
4. 4  – tan – 1 ( 2022 )

Correct answer: tan − 1 (2022) – 4 

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