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Let f and g be twice differentiable functions on such that f ''(x) = g''(x) + 6x f '

1. = 4 g '
2. – 3 = 9 f
3. = 3g
4. = 12 Then which of the following is NOT true? (1) There exists x 0  (1, 3 / 2) such that f(x 0 ) = g(x 0 ) (2) | f '( x ) – g '( x ) |  6  – 1  x  1 (3) g( – 2) – f( – 2) = 20 (4) If – 1 < x < 2, then |f(x) – g(x)| < 8

Correct answer: = 12 Then which of the following is NOT true? (1) There exists x 0  (1, 3 / 2) such that f(x 0 ) = g(x 0 ) (2) | f '( x ) – g '( x ) |  6  – 1  x  1 (3) g( – 2) – f( – 2) = 20 (4) If – 1 < x < 2, then |f(x) – g(x)| < 8

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