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Let f(  ) = ) 2 sin 1

1. 3 ( sin 2 3 sin 3 2 4 4                         and S =              2 3 ) ( ' f : ] , 0 [ . If       S , then f (   is equal to
2. 8 9
3. 2 3
4. 4 5 (4) 8 11

Correct answer: 2 3

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