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Let the tangents at t he points A (4, – 11) and B (8, – 5) on the circle x 2 + y 2 – 3 x + 10 y – 15 = 0, intersect at the point C . Then the radius of the circle, whose centre is C and the line joining A and B is its tangent, is equal to
- 13
- 4 3 3
- 3 13 2
- 13 2
Correct answer: 3 13 2
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