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Let T and C respectively be the transverse and conjugate axes of the hyperb ola 16 x 2 – y 2 + 64 x + 4 y + 44 = 0. Then the area of the region above the parabola x 2 = y + 4, below the transverse axis T and on the right of the conjugate axis C is :

1. 3 28 6 4 
2. 3 44 6 4 
3. 3 44 6 4 
4. 3 28 6 4 

Correct answer: 3 28 6 4 

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