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Let f(x) =    dx ) 3 x )( 1 x ( x 2 2 2 . If ) 6 log 5 (log 2 1 ) 3 ( f e e   , then f

1. is equal to
2. log e 17 – log e 18
3. log e 19 – log e 20
4. 2 1 ( log e 17 – log e 19) (1) 2 1 ( log e 19 – log e 17 )

Correct answer: log e 19 – log e 20

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