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The points of intersection of the line ax + by = 0, ( a b ) and the circle x 2 + y 2 – 2 x = 0 are A ( , 0) and B (1, ). The image of the circle with AB as a diameter in the line x + y + 2 = 0 is:
- x 2 + y 2 + 5 x + 5 y + 12 = 0
- x 2 + y 2 + 3 x + 5 y + 8 = 0
- x 2 + y 2 – 5 x – 5 y + 12 = 0
- x 2 + y 2 + 3 x + 3 y + 4 = 0
Correct answer: x 2 + y 2 + 5 x + 5 y + 12 = 0
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