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The locus of the mid points of the chords of the circle C 1 : ( x – 4) 2 + ( y – 5) 2 = 4 which subtend an angle  i at the centre of the circle C 1 , is a circle of radius r i . If   = 3  ,   = 3 2  and 2 3 2 2 2 1 r r r   , then  2 is equal to

1. 4 3 
2. 4 
3. 6 
4. 2 

Correct answer: 2 

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