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ExamsJEE MainGeneral

The position of a particle related to time is given by x = (5t 2 – 4t + 5) m. The magnitude of velocity of the particle at t = 2 s will be :

  1. 06 ms –1
  2. 14 ms –1
  3. 10 ms –1
  4. 16 ms –1

Correct answer: 16 ms –1

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