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ExamsJEE MainGeneral

Let x = x(y) be the solution of the differential equation 2(y + 2) log e (y + 2) dx + (x + 4 – 2log e (y + 2))dy = 0, y > –1 with x(e 4 – 2) = 1. Then x(e 9 – 2) is equal to-

  1. 3
  2. 9 4
  3. 9 32
  4. 3 10

Correct answer: 9 32

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