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2-Methyl propyl bromide reacts with C 2 H 5 O – and gives ‘A’ whereas on reaction with C 2 H 5 OH it gives ‘B’. The mechanism followed in these reactions and the products ‘A’ and ‘B’ respectively are :

1. S N 2, A = iso-butyl ethyl ether; S N 1, B = tert-butyl ethyl ether
2. S N 1, A = tert-butyl ethyl ether; S N 1, B = 2-butyl ethyl ether
3. S N 2, A = 2-butyl ethyl ether; S N 2, B = iso-butyl ethyl ether
4. S N 1, A = tert-butyl ethyl ether; S N 2, B = iso-butyl ethyl ether

Correct answer: S N 2, A = iso-butyl ethyl ether; S N 1, B = tert-butyl ethyl ether

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