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Let y = y(x), y > 0, be a solution curve of the differential equation (1 + x 2 ) dy = y(x –y) dx. If y(0) = 1 and y 2 2 = , then
- 1 3 e = e 2 2 3
- 1 3 e = e 2 5
- 1 e = e –2 2 2 3
- 1 e = e –2 2 5
Correct answer: 1 3 e = e 2 2 3
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