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What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg? (Assume dilute solution is being formed) Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is 180 g mol –1
- 3.59 g
- 3.69 g
- 4.69 g
- 2.59 g
Correct answer: 3.69 g
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