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A metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V 0 . If the same surface is il luminated with radiation of wavelength 2λ, the stopping potential becomes 4 V 0 . The threshold wavelength for this metallic surface will be :
- 3λ
- 4λ
- 2 3
- 4
Correct answer: 3λ
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