Exams › JEE Main › General
The de Broglie wavelength of a molecule in a gas at room temperature (300 K) is 1 . If the temperature of the gas is increased to 600 K., then the de Broglie wavelength of the same gas molecule becomes
- 2 1 1
- 2 1
- 2 1 1
- 2 1
Correct answer: 2 1 1
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →