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Two point charges Q each are placed at a distance d apart. A third point charge q is placed at a distance x from mid-point on the perpendicular bisector. The value of x at which charge q will experience the maximum Coulombs force is :

1. x = d
2. x = 2 d
3. x = 2 d
4. x = 2 2 d

Correct answer: x = 2 2 d

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