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Consider the reaction 4HNO 3 (  ) + 3KCl(s)  Cl 2 (g) + NOCl(g) + 2H 2 O(g) + 3KNO 3 (s) The amount of HNO 3 required to produce 110.0 g of KNO 3 is : (Given : Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.)

1. 32.2 g
2. 69.4 g
3. 91.5 g
4. 162.5 g

Correct answer: 91.5 g

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