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If f( α ) = ∫ α + 1 10 dt t 1 t log , α > 0, then f(e 3 ) + f(e –3 ) is equal to :

1. 9
2. 2 9
3. ) 10 ( log 9 e
4. ) 10 ( log 2 9 e

Correct answer: ) 10 ( log 2 9 e

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