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Let the plane ax + by + cz = d pass through (2, 3, –5) and is perpendicular to the planes 2x + y – 5z = 10 and 3x + 5y – 7z = 12. If a, b, c, d are integers d > 0 and gcd (|a|, |b|, |c|, |d|) = 1, then the value of a + 7b + c + 20d is equal to :
- 18
- 20
- 24
- 22
Correct answer: 22
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