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If two distinct points Q, R lie on the line of intersection of the planes – x + 2 y – z = 0 and 3 x –5 y + 2 z = 0 and PQ = PR = 18 where the point P is (1, –2, 3), then the area of the triangle PQR is equal to =
- 38 3 2
- 38 3 4
- 38 3 8
- 3 152
Correct answer: 38 3 4
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