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ExamsJEE MainGeneral

The differential equation of the family of circles passing through the points (0, 2) and (0, –2) is

  1. 2xy dx dy + (x 2 – y 2 + 4) = 0
  2. 2xy dx dy + (x 2 + y 2 – 4) = 0
  3. 2xy dx dy + (y 2 – x 2 + 4) = 0
  4. 2xy dx dy – (x 2 – y 2 + 4) = 0

Correct answer: 2xy dx dy + (x 2 – y 2 + 4) = 0

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