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ExamsJEE MainGeneral

Let x(t) = 2 2 cos t t 2 sin and y(t) = 2 2 sin t t 2 sin , t ∈ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π 2 , 0 . Then 2 2 2 dx y d dx dy 1 ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + at t = 4 π is equal to

  1. 3 2 2 −
  2. 3 2
  3. 3 1
  4. 3 2 −

Correct answer: 3 2 −

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