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A slab of dielectric constant K has the same cross-sectional area as the plates of a parallel plate capacitor and thickness 4 3 d , where d is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be: (Given C 0 = capacitance of capacitor with air as medium between plates.)

1. K 3 KC 4 0 +
2. K 3 KC 3 0 +
3. 0 KC 4 K 3 +
4. K 4 K +

Correct answer: K 3 KC 4 0 +

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