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A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of: (Given, Planck’s constant = 6.6 × 10 –34 Js).
- 2.10 × 10 –34 Js
- 1.05 × 10 –34 Js
- 3.15 × 10 –34 Js
- 4.2 × 10 –34 Js
Correct answer: 1.05 × 10 –34 Js
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