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A projectile is launched at an angle ' α ’ with the horizontal with a velocity 20 ms –1 . After 10s, its inclination with horizontal is ‘ β ’ The value of tan β will be ( g = 10 ms –2 ) .

1. tan α + 5sec α
2. tan α – 5sec α
3. 2tan α – 5sec α
4. 2tan α + 5sec α

Correct answer: tan α – 5sec α

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