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If ∫ + dx x 1 x – 1 x 1 = g(x) + c, g

1. = 0, then g ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ 2 1 is equal to
2. log e 3 1 3 1 – 3 π + ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ +
3. log e 3 1 – 3 1 3 π + ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ +
4. log e 3 – 1 – 3 1 3 π ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ + (4) 6 – 1 3 1 – 3 log 2 1 e π ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ +

Correct answer: = 0, then g ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ 2 1 is equal to

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