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If the system of equations α x + y + z = 5, x + 2y + 3z = 4, x + 3y +5z = β has infinitely many solutions, then the ordered pair ( α , β ) is equal to:

1. (1, –3)
2. (–1, 3)
3. (1, 3)
4. (–1, –3)

Correct answer: (1, 3)

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