Exams › JEE Main › General
f, g : R → R be two real valued functions defined as f(x) = ⎩ ⎨ ⎧ ≥ < + − 0 x , e 0 x |, 3 x | x and g(x) = ⎪ ⎩ ⎪ ⎨ ⎧ ≥ + < + 0 x , k x 4 0 x , x k x 2 1 2 where k 1 and k 2 are real constants. If (gof) is differentiable at x = 0, then (gof) (–4) + (gof)
- is equal to :
- 4(e 4 + 1)
- 2(2e 4 + 1)
- 4e 4 (4) 2(2e 4 – 1)
Correct answer: 4e 4 (4) 2(2e 4 – 1)
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