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The negation of the Boolean expression ((~ q) ∧ p) ⇒ ((~ p) ∨ q) is logically equivalent to :

1. p ⇒ q
2. q ⇒ p
3. ~ (p ⇒ q)
4. ~ (q ⇒ p)

Correct answer: ~ (p ⇒ q)

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