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Let E 1 and E 2 be two events such that the conditional probabilities P(E 1 | E 2 ) = 2 1 , P(E 2 | E 1 ) = 4 3 and P(E 1 ∩ E 2 ) = 8 1 . Then -

1. P(E 1 ∩ E 2 ) = P(E 1 ) · P(E 2 )
2. P(E ′ 1 ∩ E ′ 2 ) = P(E ′ 1 ) · P(E 2 )
3. P(E 1 ∩ E ′ 2 ) = P(E 1 ) · P(E 2 )
4. P(E ′ 1 ∩ E 2 ) = P(E 1 ) · P(E 2 )

Correct answer: P(E 1 ∩ E ′ 2 ) = P(E 1 ) · P(E 2 )

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