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The number of choices for Δ ∈ { ∧ , ∨ , ⇒, ⇔ }, such that (p Δ q) ⇒ ((p Δ ~ q) ∨ ((~p) Δ q)) is a tautology, is -

1. 1
2. 2
3. 3
4. 4

Correct answer: 2

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