Exams › JEE Main › General
For a reaction at equilibrium A(g) B(g) + 2 1 C(g) the relation between dissociation constant (K), degree of dissociation ( α ) and equilibrium pressure (p) is given by :
- K = ) – 1 ( 2 3 1 p 2 1 2 3 2 1 α ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ α + α
- K = ( ) ) – 1 ( 2 p 2 1 2 1 2 3 α α + α
- K = ) – 1 ( 2 3 1 ) p ( 2 1 2 3 α ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ α + α
- K = 2 1 2 3 ) – 1 ( ) 1 ( ) p ( α α + α
Correct answer: K = ( ) ) – 1 ( 2 p 2 1 2 1 2 3 α α + α
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