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Consider the following pairs of electrons (A) (a) n = 3, l = 1, m 1 = 1, m s = + 2 1 (B) (a) n = 3, l = 2, m 1 = –2, m s = – 2 1 (b) n = 3, l = 2, m 1 = 1, m s = + 2 1 (b) n = 3, l = 2, m 1 = –1, m s = – 2 1 (C) (a) n = 4, l = 2, m 1 = 2, m s = + 2 1 (b) n = 3, l = 2, m 1 = 2, m s = + 2 1 The pairs of electrons present in degenerate orbitals is /are:

1. Only (A)
2. Only (B)
3. Only (C)
4. (B) and (C)

Correct answer: Only (B)

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